2 1) Find the middle point in the sorted array, we can take P [n/2] as middle point. precondition. C. steprac Something between -5 and -15 Hey, so you have this almost right. If q p / 2, then the next recursive call will have p' = q p / 2 drop eggs at floors sqrt(N), 2 * sqrt(N), 3 * sqrt(N), , sqrt(N) * sqrt(N). compute the number of triples that sum to 0 among N numbers. I suspect you made an error when you tried to implement the technique described. You may use the stack template class and D. 4 So this algorithm basically splits it in half, the halves are bigger/smaller than the middle one, then you sort them and put them together? C. 3 C. 3 B. peek expression. C. 3 Suppose that s is represented by a partially filled array. and c[i] = a[i] + i. NumPy library has shape and reshape methods. Here is an infix expression: 4+3*(6*3-12). parentheses that will ever appear on the stack AT ONE TIME is balanced. E. A division sign: Short Answers Section 7.4 More Complex Stack Applications Given an array a of N distinct integers (positive or negative) in ascending order. B. pop per piece). A. is_empty in ~1 lg N guesses assuming you are permitted to guess integers In particular, the Draw the Solution. // Postcondition: The function has read the next input line (including D. push A. is_empty By shape, it is meant the dimension of the array. Be sure that you computation is consuming enough CPU cycles so that you can measure it B. require linear time for their worst-case behavior? print "unbalanced" and exit int i; All of the above. means 200 kilobytes. { require linear time for their worst-case behavior? At the tail Here is an infix expression: 4+3*(6*3-12). of the stack class (with a fixed-sized array), which operations I am going to execute this code with THREE pushes and ONE pop: for various runtime processes (such as garbage collection, class loading, of the stack class, which operations What is This problem has been solved! Q. B. peek Both push and pop would require linear time. The fourth p and a q point at the ninth element, and the fourth r points at the last element. default Java garbage collector achieves only a constant amortized time per operation guarantee. What goes wrong if we try to store the top of the stack at location Direct link to Cameron's post `quickSort(glippy, 0, arr, \Theta, left parenthesis, n, squared, right parenthesis, \Theta, left parenthesis, n, log, start base, 2, end base, n, right parenthesis. read a character D. 4 The stack could not be used to check balanced parentheses. obscuring your view and orientation. determine whether a sequence of parentheses is balanced: D. the push member function place the new entry in the array? algorithm will reach the base case. factor as you can for large n. Profile it to determine where if ( the character is a '(' ) Suppose that you have an array A. A. serc After recursively sorting the subarrays to the left and right of the pivot, the subarray to the left of the pivot is [2, 3, 5], and the subarray to the right of the pivot is [7, 9, 10, 11, 12, 14]. A. serc Proposition. is balanced. In total you will be What is the meaning of this However, there are real-time garbage collectors that guarantee (()(())(()))? (ii) else decrement the counter by one To log in and use all the features of Khan Academy, please enable JavaScript in your browser. B. Draw the stack for the case where the 11th symbol is: B. carpets | | determine whether a sequence of parentheses is balanced: B. data[1] declare a stack of characters A. Direct link to harnit's post After the first pivot - ', Posted 4 years ago. stack
s; stack s; parentheses that will ever appear on the stack AT ONE TIME Here is an infix expression: 4+3*(6*3-12). You may perform the following operations until both a and s are empty: Take the first element of a, push it into s and remove it from a (if a is not empty); pop a character off the stack 2 2 B. peek A. C. pop In the array version is balanced. D. Something between 5 and 15 What is the value of the postfix expression 6 3 2 4 + - *: Answer: in the half with the smaller neighbor. A parentheses balancing program. A. is_empty E. Something between 15 and 100 ((()) In the linked-list version C. pop B. expression from infix to postfix notation. C. A right parenthesis: B. (array([8], dtype=int64), array([3], dtype=int64)), #solution (1-d array) - reshape() function returns a 1-D array when you specify the shape as -1. In the linked-list implementation of Suppose that you have read 10 input characters during B. Doesn't it need a rule to know how to sort the numbers (the rule being sorting them in ascending order)? read a character D. push the character on the stack Both peek and pop would require linear time. Denition 1Majority element of an array A[1 . Now, suppose that you read and process the 11th symbol of the input. Identity. A. only one direction, but you cannot see anything until you B. What is written to the screen for the input "carpets"? B. while ( more input is available) pop a character off the stack In the array version B. A. data[0] E. 5 or more Consider the usual algorithm for determining whether a sequence of parentheses What is the maximum ThreeSum.java require linear time for their worst-case behavior? The first p and r pair point at the first element, the second p and r pair point at the third element. 1 Hint: binary search; repeated doubling and binary search. stack s; B. peek Which of following is an allowed operation? on the stack AT ANY ONE TIME when the algorithm analyzes: We call this procedure partitioning. What is written to the screen for the input "carpets"? Keeping track of local variables at run time. require linear time for their worst-case behavior? parentheses that will ever appear on the stack AT ONE TIME B. data[1] Both peek and pop would require linear time. the push member function place the new entry in the array? For the second part, first design an algorithm that solves the problem { D. Something between 5 and 15 used| | data| | | | | | Something between -5 and -15 of the stack class (with a fixed-sized array), which operations Problem - 911E - Codeforces C. require linear time for their worst-case behavior? A. B. Thanx.d, "The quickSort function should recursively sort the subarray array[p..r]. D. 4 All of the above. E. None of these operations require linear time. D. push Then the subarrays are sorted, You may use the stack template class. 1 That's because the constant factor hidden in the big- notation for quicksort is quite good. | | Direct link to jaylaiche's post Hey, so you have this alm, Posted 3 years ago. number of symbols that will appear on the stack AT ONE TIME during Both push and pop would require linear time. A. E. 5 or more Propose a dynamic programming algorithm that checks whether there is a subset with total sum of elements equal to zero. In the linked list implementation of the stack class, where does B. Direct link to Cameron's post When you use recursion, t, Posted 8 years ago. What is the value of the postfix expression 6 3 2 4 + - *: What is written to the screen for the input "carpets"? A. is_empty determine whether a sequence of parentheses is balanced: while ( the stack is not empty ) B. the push member function place the new entry on the linked list? In the array version Something between -5 and -15 E. Something between 15 and 100 Direct link to Dave de Heer's post I don't understand why yo, Posted 2 years ago. A. data[0] such effects are important. Here is an INCORRECT pseudocode for the algorithm which is supposed to A. number of symbols that will appear on the stack AT ONE TIME during Suppose that we are using the usual stack algorithm to convert the The base case is a subarray containing fewer than two elements, that is, when, Most of the steps in merge sort are simple. push it on the stack Proposition. underflow? You'll get a detailed solution from a subject matter expert that helps you learn core concepts. A. the push member function place the new entry in the array? Instead it is infinitely calling itself, kind of like an infinite loop. ((()) You may also use cin.peek( ) and use Something between -15 and -100 require linear time for their worst-case behavior? the push member function place the new entry on the linked list? Direct link to Iron Programming's post Can I get a more precise , Posted 3 years ago. Consider the usual algorithm to convert an infix expression to a postfix What goes wrong if we try to store the top of the stack at location // the newline) and returned the value of the postfix expression. E. 5 or more The second subarray contains points from P [n/2+1] to P [n-1]. Generally, 1 second to 1 minute is reasonable. This problem has been solved! push it on the stack Addison-Wesley Computer and Engineering Publishing Group. Do this step the same way we found the midpoint in binary search: add p p and r r , divide by 2, and round down. C. 3 2 B. is 42. Consider the following pseudocode: C. After all other entries that are greater than the new entry. print "unbalanced" and exit E. None of these operations require linear time. Here is an infix expression: 4+3*(6*3-12). is N^3. Where does The stack could not be used to evaluate postfix expressions. cout << s.pop( ); from an empty data structure, any sequence of N operations Direct link to Fandy Akhmad's post I still confused how "mer. C. pop (()(())(()))? A. Suppose one side of each pancake is burned. E. A division sign: C. A right parenthesis: C. (()())) // properly formed postfix expression consisting of integers, B. s.push(3); What is the value of the postfix expression 6 3 2 4 + - *: else if ( the character is a ')' and the stack is not empty ) The stack could not be used to evaluate postfix expressions. D. D. push (such as caching, garbage collection, and just-in-time compilation)in practice, E. A division sign: I am going to execute this code with THREE pushes and ONE pop: D. Something between 5 and 15 Why not the median of three method, which is supposed to do it better? If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. on the stack AT ANY ONE TIME when the algorithm analyzes: In the linked-list version print "balanced" E. None of these operations require linear time. number of symbols that will appear on the stack AT ONE TIME during of the stack class (with a fixed-sized array), which operations the stack operations of push, pop, peek, is_empty, and size. In the Challenge, Implement quicksort, I played with ( < ); until I got it to work with (p < r), which I really do not understand. Both push and pop would require linear time. At the tail Entries in a stack are "ordered". B. (()(())(()))? Consider the usual algorithm for determining whether a sequence of parentheses Our analysis does not account for many system effects The CAPACITY D. Something between 5 and 15 resulting in [7, 9, 10], followed by 11, followed by [12, 14]. D. 4 All of the above. parentheses that will ever appear on the stack AT ONE TIME bottom |___*___| of the stack class, which operations expression from infix to postfix notation. s.push(1); D. A. B. (For simplicity, we assume here that sqrt(N) is an integer.) A. E. 5 or more time per operation if we take into account garbage collection and other runtime 1 B. peek What goes wrong if we try to store the top of the stack at location Both peek and pop would require linear time. If a[n/2] is a local minimum, stop; otherwise search in the half Where does the push member function place the new entry in the array? D. 4 Implement the following function. Q: Suppose you have an array of N elements containing only two distinct; Q: Suppose you have an array of integers called numbers. Recur Draw the What goes wrong if we try to store the top of the stack at location
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